On 2011-03-14, at 14:29, Jorge wrote: > On 14/03/2011, at 18:32, P T Withington wrote: >> On 2011-03-13, at 18:15, Juan Ignacio Dopazo wrote: >>> >>> >>> The idea behind it was to be able to walk down the prototype chain by doing >>> o.constructor.prototype.contructor.proto... But then I realized that's not >>> the case even in today's javascript. >> >> I agree that we need this. (...) > > Isn't that the purpose of Object.getPrototypeOf() ?
If I have a class `c` whose superclass is `s`, I'm trying to understand how I can get from an object that is an instance of `c` to the superclass. I believe the current desugaring that Alan proposed, which obeys Brendan's recommendation that `constructor` be a property of the prototype results in: o = new c(); o.constructor === c o instanceof c => true o instanceof s => true o.constructor.prototype instanceof s => true but: o.constructor.prototype.constructor === c ? I don't see how I can recover `s` from `o` (or `c`), which seems like a useful operation. What am I missing? _______________________________________________ es-discuss mailing list [email protected] https://mail.mozilla.org/listinfo/es-discuss
