var x = /\1/; According to 15.10.2.11, the RegExp snippet above should throw something as there aren't any capturing parenthesis within the RegExp, yet one is referenced. Just now noticed that step 4 of 15.10.2.9 is more precise and shows a SyntaxError gets thrown. Isn't the snippet then potentially valid ES5 code through Chapter 16's SyntaxError extension clause?
Thanks! Dave
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