Sorry for sounding harsh, but I’m really just curious: The example below seems
awfully contrived (wouldn’t even single inheritance easily do?) and I don’t see
|super| anywhere in it. Have you ever found the need for |super| in a generic
function?
Even when we get traits, I don’t see myself as ever needing super-calls in
trait methods. That’s because |super| is a construct for subclasses, while
traits, in a way, are abstract superclasses.
> Now try to imagine many other object would like to implement the
> 3Dpoint#isPositive method using 3DPoint as interface but without necessarily
> extending it .... blah, I know this example is crap so I will think about a
> better one.
>
> function Entity() {} // no point by default
> Entity.prototype.setPoint = function (x, y, z) {
> 3DPoint.call(this, x, y, z);
> this.hasPoint = true;
> return this;
> };
> Entity.prototype._isPositive = 3DPoint.prototype.isPositive;
> Entity.prototype.isPositive = function () {
> return this.hasPoint && this._isPositive();
> };
> Entity.prototype.hasPoint = false;
>
> (new Entity).setPoint(1, 2, 3).isPositive(); // boom ? or super is bound to
> Point ?
--
Dr. Axel Rauschmayer
[email protected]
home: rauschma.de
twitter: twitter.com/rauschma
blog: 2ality.com
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