Herby Vojčík wrote:
function foo (...args) {
let {0:b, 0:{x,y}, foo, bar, baz} = args;
...
}
That's not right, if you go the long way round you want:
function foo (...args) {
let {0:b, 0:{x,y}, 1:foo, 2:bar, 3:baz} = args;
...
}
but as Allen just suggested, the right way to do it is:
function foo ({b}, ...args) {
let {x,y} = b;
let [foo, bar, baz] = args;
...
}
/be
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