Oops, missing one line below: Brendan Eich wrote:
Which one? If you mean let*, so thatfunction f(a = a, b = b*a) { return [a, b]; } var a = 42;
var b;
console.log(f()) // [42, NaN] console.log(f(1)) // [1, NaN] console.log(f(1,2)) // [1, 2]
Otherwise b*a will throw on unbound b. /be _______________________________________________ es-discuss mailing list [email protected] https://mail.mozilla.org/listinfo/es-discuss
