On May 21, 2013, at 1:23, "Anne van Kesteren" <[email protected]<mailto:[email protected]>> wrote:
On Tue, May 21, 2013 at 6:20 AM, Domenic Denicola <[email protected]<mailto:[email protected]>> wrote: As long as the contract that `map.set(x, y); map.get(x) === y` works for any `x` and `y`, then you're probably fine. I think it would have to subclass those methods by using toString() on the argument passed. It seems that would still be Map-like though. Hmm, so that invariant wouldn't hold? I assume `has` would be similarly broken? Seems… not so Map like, besides perhaps having some operations with the same name as Map's. Relevant: http://en.wikipedia.org/wiki/Liskov_substitution_principle
_______________________________________________ es-discuss mailing list [email protected] https://mail.mozilla.org/listinfo/es-discuss

