On Tue, Oct 22, 2013 at 2:34 PM, Benjamin (Inglor) Gruenbaum < [email protected]> wrote:
> On Tue, Oct 22, 2013 at 8:10 PM, Russell Leggett < > [email protected]> wrote: > >> > Revised algorithm: > > 1. If receiver has protocol method symbol as a property, use that as > override. > > 2. Try to use protocol methods - start by checking receiver type > mapping, then check up type hierarchy for any matches, and finally if no > matches, use the default if defined. > > 3. Finally, if no matches and no default, check prototype for method of > same name. > > Does that sound better? > > Much :) > Actually, let me revise 3: 3. Finally, if no matches and no default, attempt to call a method of the same name (not affected by variable name or aliasing) on the receiver. Something like this: const P = new Protocol("foo"); // naive, non-native implementation of P.methods.foo would be something like function foo(...args){ if(P.symbols.foo in this){ //P.symbols holds a symbol for each method return this[P.symbol.foo](...args); }else if(P.contains(Object.getPrototypeOf(this))){ //contains and lookup might be backed by a weakmap or something, //but it would also need to go up the type chain let myFoo = P.lookup(Object.getPrototypeOf(this)).foo; return this::myFoo(...args); }else if(P.getDefaults().hasOwnProperty("foo")){ let defaultFoo = P.getDefaults().foo; return this::defaultFoo(...args); }else{ this.foo(...args); } } If this seems acceptable, I'll update the gist. - Russ
_______________________________________________ es-discuss mailing list [email protected] https://mail.mozilla.org/listinfo/es-discuss
