Unless I misunderstood your idea, `||=` makes me naturally think about `+=` so if
`i += n;` means `i = i + n` then `o.name ||= value` means `o.name = o.name || value` and this would be, according with all these years in ES3, the least surprising behavior which is **way different** from checking if `name` is not defined. Accordingly, I wonder ... 1. what if `name` was inherited with a non _falsy_ value ? 2. what if `name` was defined as `undefined` ? 3. should that silently fail if `name` was already defined ? Cheers On Sun, Feb 9, 2014 at 2:17 AM, Hemanth H.M <[email protected]> wrote: > Something like `var foo = {}; foo.bar ||= 3` would be very useful. > > But not sure how something like `obj['name']['maxlength']` be reduced to > shorthand check if 'name' is not defined. > > > > -- > *'I am what I am because of who we all are'* > h3manth.com <http://www.h3manth.com> > *-- Hemanth HM * > > _______________________________________________ > es-discuss mailing list > [email protected] > https://mail.mozilla.org/listinfo/es-discuss > >
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