Le 15 mai 2014 à 20:17, Rick Waldron <[email protected]> a écrit :
>
>
> If the "." was on the other side?
>
> AccessorAssignmentOperator :
> .= IdentifierName
>
>
> var string = " a ";
> string .= trim(); // would throw if no `trim` method existed for `string`
>
> string; // "a";
>
>
> Where ".=" means assign the result of "Property Accessors Runtime Semantics
> Evaluation" with lval and rval in appropriate positions (TBH, I'm sure I
> missed something in there)
There is an interesting question of precedence/associativity. Normally, for a
binary operator @, the two lines are more or less the equivalent:
a @= foo(bar).baz() + quax
a = a @ (foo(bar).baz() + quax)
But when you write, say
str .= replace(/_/g, ' ').trim() + ' foo'
you probably don't mean
str = str.(replace(/_/g, ' ').trim() + ' foo')
but rather:
str = (str.replace)(/_/g, ' ').trim() + ' foo'
—Claude
_______________________________________________
es-discuss mailing list
[email protected]
https://mail.mozilla.org/listinfo/es-discuss
