On Tue, Jun 17, 2014 at 2:49 PM, Jasper St. Pierre <[email protected]> wrote: > How would > > constructor() { > if (rand() > 0.5) > super("A"); > } > > behave?
SyntaxError. > We could prevent this behavior by making sure that super(); must be the > first statement in a constructor, [...] That is what I proposed. > [...] but that means that the subclass can't > really influence the parent constructor execution at all. Any class can explicitly define a `static [Symbol.new]()` method, if desired. Or the constructor method can return another object, so that the base class @@new method is called, but the object it created is thrown away. I should have mentioned that -- I would retain this behavior, which is already in ES6, but none of the examples used it so I forgot to say so. Anyway --- skipping a base class constructor is not a normal thing to do. It shouldn't be the default. -j _______________________________________________ es-discuss mailing list [email protected] https://mail.mozilla.org/listinfo/es-discuss
