On second thought, since this is a method, directly calling the method name loses `this` value, so people might not do it very often. If recursion is needed, they might just do `this.next()`.
The `name` property being set is trivia, and `a.next.name === “next”` sounds reasonable. So, no more complain. :) > On Dec 17, 2014, at 12:32 PM, Glen Huang <[email protected]> wrote: > > Got it. Thank you. > > Was kinda hoping I was wrong though. > > ```js > let next = () => console.log(1); > let a = { next() { console.log(2); next() } }; > a.next(); > ``` > > I guess people would incline to guess this is a recursion, since the method > syntax isn’t as obvious as `{ next: function () {} }` that you are creating > an anonymous function. Also from the spec, I believe `a.next.name` has the > value “next” in the snippet, this looks like a (false) indication that the > function created is not anonymous. > >> On Dec 17, 2014, at 12:13 PM, Rick Waldron <[email protected] >> <mailto:[email protected]>> wrote: >> >> >> >> On Tue Dec 16 2014 at 11:03:43 PM Glen Huang <[email protected] >> <mailto:[email protected]>> wrote: >> To rephrase the problem: >> >> Assuming `next` was never defined. >> >> ```js >> let a = { next() { next() } }; >> a.next(); >> ``` >> >> The result of running this code is runtime error or infinite recursion? >> >> I tried to find the answer in the spec, but the initialization and calling >> of a function object is a bit overwhelming for me. >> >> The evaluation of FunctionExpression contains a step "Call the >> CreateImmutableBinding concrete method of envRec passing name as the >> argument.” together with "Call the InitializeBinding concrete method of >> envRec passing name and closure as the arguments. I" guess that’s the steps >> enable directly calling function name in the function body? >> >> Correct. This is defines the runtime evaluation semantics for the `next: >> function next() { }` part of `let a = { next: function next() { } }`. >> >> >> And since DefineMethod doesn’t have such steps, is it correct to assume the >> above snippet should result in a runtime error? >> >> It would be a ReferenceError, because next is not defined. >> >> Rick >
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