No that would not work either. You want an object that has its [[Prototype]] set to MyClass.prototype.
On Mon, Feb 16, 2015, 02:55 Marius Gundersen <[email protected]> wrote: > >>> The purpose would be defining a class whose instances don't have > Object.prototype on their prototype chain. If "extends null" doesn't work, > then I think you'd have to do something like this to achieve the same? > >>> > >>> function NullBase() {} > >>> NullBase.prototype = Object.create(null); > >>> > >>> class C extends NullBase {} > >>> > > Can't this be solved by returning a null object from the constructor? > > ```js > class Null{ > constructor() { > return Object.create(null); > } > } > > class MyClass extends Null{ > > } > let foo = new MyClass(); > foo.toString() //ReferenceError > ``` > > Marius Gundersen >
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