Neither the base (parent) nor derived (child) class requires a constructor, nor
does the child class require a `super()` call. If you omit either constructor,
an assumed one is present. However, if you *do* declare a constructor in a
derived class, you'll need to call `super()` in it.
So, to the point of your original question, this is totally valid:
```js
class A {
foo() { console.log("A:foo"); }
}
class B extends A {
bar() { super.foo(); }
}
var x = new B();
x.bar(); // A:foo
```
See it in action:
http://babeljs.io/repl/#?experimental=false&evaluate=true&loose=false&spec=false&playground=false&code=class%20A%20%7B%0A%20%20foo()%20%7B%20console.log(%22A%3Afoo%22)%3B%20%7D%0A%7D%0A%0Aclass%20B%20extends%20A%20%7B%0A%20%20bar()%20%7B%20super.foo()%3B%20%7D%0A%7D%0A%0Avar%20x%20%3D%20new%20B()%3B%0A%0Ax.bar()%3B
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