On May 7, 2015, at 12:50 PM, Francisco Tolmasky wrote:
> In the existing implementations I’ve tried, it appears I can’t do this:
>
> class SuperFunction extends Function { }
>
> (also tried with constructor(str) { super(str) })
>
> It “works”, but the resulting new SuperFunction(“return 5”) is just a
> Function, not a SuperFunction. Is Function meants to be an exception to the
> subclassing built-ins, or should it also work?
Nope, it's supposed to work. `Object.getPrototypeOf(new SuperFunction("")`
should be SuperFunction.prototype and `new SuperFunction("") instanceof
SuperFunction` should be true.
You need to file a bug report on the implementations where you tried it.
Sounds like they still have some work to do
Allen
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