> Le 12 mai 2015 à 04:51, Glen Huang <[email protected]> a écrit :
>
> However, forcing super has one major drawback: it becomes cumbersome when you
> don't want to call superclass's constructor(), that you want to define a new
> constructor() to override it.
>
> When that happens, you have two choices:
>
> 1. don't use "this", create a new object and return it.
> 2. use the old way to create "class"
To be short, for me, there are two more choices:
3. maybe subclassing that particular class is not the correct abstraction here;
4. correct the design of the super-constructor, so that it is able to just do
the minimum required stuff.
Also, as an alternative to your choice #2, there is the following possibility
that I don't propose very seriously, although I wonder if it might be more
semantically correct than subclassing in your use case. Instead of `class B
extends A { }`, write:
```
class B { }
Object.setPrototypeOf(B, A)
Object.setPrototypeOf(B.prototype, A.prototype)
```
—Claude
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