It makes things like this:
let x=0;
for (let x of (x=2, obj) {...}
produce an error.
Essentially it is creating a TDZ for 'x' that spans the of expression.
It doesn 't make a difference whether the TDZ binding for x is mutable
or immutable because the binding is never initialized so any reference
to it will produce an error.
Allen
On Wed, 13 May 2015 15:41:36 +0200, Axel Rauschmayer wrote:
https://people.mozilla.org/~jorendorff/es6-draft.html#sec-runtime-semantics-forin-div-ofheadevaluation-tdznames-expr-iterationkind-labelset
I don’t understand step 2: the temporary environment TDZ is created
for step 3. All bindings of TDZ are mutable (even the `const`-declared
ones). It looks like TDZ is thrown away afterwards. Why is this step
necessary? Why are all bindings mutable
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