...but you can do this: [].push.apply(arr1,arr2);
On Thu, May 14, 2015 at 9:25 AM, Emanuel Allen <[email protected]> wrote: > Surprise that I can't do arr1.forEeach(arr2.push); > > Will throw an error. > > Using bind as: > > push = arr2.bind(push); > arr1.forEeach(push); > > Works... And not work. Seem to push individual elements and after every > second element, it'll push the hold array.. And after and before each index > that hold the array there are duplicate of that element preceding and > following: > > [1,2,array,2,3]//not this is with shift method > [1,2,array,3,2]//note that this is with push > > > JS4L > _______________________________________________ > es-discuss mailing list > [email protected] > https://mail.mozilla.org/listinfo/es-discuss >
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