Pointing out that I'm replying to a message with an empty subject - using the correct original title here
---------- Forwarded message ---------- From: Rock <[email protected]> Benjamin Gruenaum, Andrea Giammarchi, you are wrong about RegExp: ```js var re = /./; new RegExp(re) === re; // false RegExp(re) === re; // true Nice catch. This is states explicitly as a difference to the rule here http://es5.github.io/#x15.10.3.1 > If pattern is an object R whose [[Class]] internal property is "RegExp" and flags is undefined, then return R unchanged. Otherwise call the standard built-in RegExp constructor (15.10.4.1) as if by the expression new RegExp( pattern, flags) and return the object constructed by that constructor. I didn't notice that - thanks.
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