```js const a = [1, 2, 3] .map(square) .map(x => console.log(x) || x ) .map(plus1) .reduce(add); ```
Regards On Fri, Oct 16, 2015 at 10:13 AM, Niloy Mondal <[email protected]> wrote: > Currently, `Array.prototype.forEach` returns `undefined`. It would be more > useful if it returns the array itself. > > Say I have written some code like this... > > ```js > const a = [1, 2, 3] > .map(square) > .map(plus1) > .reduce(add); > ``` > > For some reason, I am not getting the expected output. For debugging, I > would > like the print the values after each step. My first initial reaction is to > put a `forEach` step in between and print the values like so... > > ```js > const a = [1, 2, 3] > .map(square) > .forEach(x => console.log(x)) > .map(plus1) > .reduce(add); > ``` > > Unfortunately, this does not work as `forEach` returns `undefined`. I now > have > to comment out all the code below it. Having the _plug and play_ behaviour > for > `forEach` would be very convenient. > > _______________________________________________ > es-discuss mailing list > [email protected] > https://mail.mozilla.org/listinfo/es-discuss > >
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