Bradley Meck wrote:
>> 1. every call to `new Foo(...args)` creates a distinct object not
>> reference-equal to any other such call.
>
> Would this mean
>
> ```
> function factory() { return []; }
> ```
>
> would qualify as a constructor?I'm thinking of that as a necessary, but not a sufficient condition. If it fails that test it cannot be a constructor. It's clear that there are other tests. It's not clear to me what they are. -- Scott _______________________________________________ es-discuss mailing list [email protected] https://mail.mozilla.org/listinfo/es-discuss
