> Le 27 juin 2017 à 22:19, Mike Samuel <[email protected]> a écrit : > > On Tue, Jun 27, 2017 at 4:13 PM, Isiah Meadows <[email protected]> wrote: >> For what it's worth, for most practical purposes, `arr.sort((a, b) => b - >> a))` works well enough. (The only thing it doesn't work well with are NaNs, >> but in practice, those almost never occur.) > > Don't numeric comparison operators typically sort -0 before +0? > > ((a,b)=>b-a) is also problematic for an array that contains two or > more infinite values with the same sign and one or more finite values > since isNaN(Infinity-Infinity). That NaN from the comparator can be > triggered or not based on details of the sorting algo and the precise > placement on the Infinities.
When the comparison function produces NaN, it is treated the same way as 0; so no it is not a problem for infinities. More precisely, because `(Infinity - Infinity)` is NaN, `Infinity` is treated as “equal” to `Infinity`, which is correct. It is an issue with `NaN`, because `NaN` will be treated as “equal” to any value. —Claude _______________________________________________ es-discuss mailing list [email protected] https://mail.mozilla.org/listinfo/es-discuss
