Ah yes, woods, I was looking at the trees.

Still, to carry on with the concise style:

```js
const minMax = (arr=[]) => arr.reduce(
  ([min=Infinity, max=-Infinity], curr) => [ min < curr ? min : curr, max >
curr ? max : curr ], []
)

```

On Mon, 2 Oct 2017 at 16:55 Xavier Stouder <[email protected]> wrote:

> Same for Michael. Useless to not use a reducer instead of Math.min and
> Math.max if it has worth performance.
>
> Just to be clear, the fact is that your function approximately costs:
> Math.min: one loop over the array
> Math.max: one loop over the array
> Math.minMax: one loop over the array
>
> Math.minMax do in one pass what Math.min and Math.max do in two passes.
> That's the key point.
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>
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