Yeah, I was more focused on the static class side of things, because I
thought they were referring to that. Class instance fields are
different, and so of course, those are never set on the prototype
unless for whatever reason, the parent constructor returns
`Object.getPrototypeOf(this)` instead of letting it default to the
normal `this`.

My bad, and you are correct.

-----

Isiah Meadows
[email protected]
www.isiahmeadows.com

On Sun, Aug 26, 2018 at 12:20 PM Logan Smyth <[email protected]> wrote:
>
> Static class fields run their initializers and define the properties at 
> declaration time, and class constructors have the parent class as the 
> `[[Prototype]]`, so static field values are inherited. I think this is adding 
> to confusion though, because while that's absolutely true, that is not 
> applicable in the same way to non-static class fields, which is what this 
> original email is focused on. You could indeed also address this with static 
> properties in a proper ES6 environment as
> ```
> class Base {
>   static idAttribute = "id";
>
>   constructor() {
>        this.idAttribute = new.target.idAttribute;
>   }
> }
> class Derived extends Base {
>   static idAttribute = "_id";
>
>   constructor() {
>        super();
>   }
> }
> ```
>
> On Sun, Aug 26, 2018 at 10:35 AM Isiah Meadows <[email protected]> wrote:
>>
>> Every object, including functions, have an internal prototype. Functions 
>> normally have one set to `Function.prototype`, and objects normally inherit 
>> from `Object.prototype` at least indirectly. But because of how prototypes 
>> work, the only requirement for something to be used as a prototype is that 
>> it must be an object. So you can do `Object.create(someFunction)` and 
>> although you can't call it (it's not a callable object), that object 
>> inherits all the properties and methods from that function. `class` in 
>> JavaScript is just sugar over a common pattern (really complex sugar 
>> requiring `new.target` to emulate, but still sugar), not an entirely new 
>> concept, and it all builds off of prototypes. Specifically, the instance 
>> prototype inherits from the parent prototype, and the class constructor 
>> itself inherits from the parent constructor. That's why if you declare a 
>> static `call` method on a parent class, you can still access and use it in 
>> the subclass.
>> On Sat, Aug 25, 2018 at 19:58 Ben Wiley <[email protected]> wrote:
>>>
>>> How can they be prototypically inherited if they don't live on the 
>>> prototype? I feel like I'm missing something.
>>>
>>> Le sam. 25 août 2018 19 h 53, Isiah Meadows <[email protected]> a 
>>> écrit :
>>>>
>>>> Class fields are prototypically inherited just like via `Object create`. 
>>>> This is more useful than you might think, and it's the main reason anyone 
>>>> actually cares about static fields beyond namespacing.
>>>> On Sat, Aug 25, 2018 at 14:36 Ben Wiley <[email protected]> wrote:
>>>>>
>>>>> All this just reminds me of *my opinion* that class fields is a borrowed 
>>>>> concept from statically typed languages that is misplaced in a 
>>>>> dynamically typed languages like JavaScript.
>>>>>
>>>>> In C++ I use class fields to declare what properties will be allocated 
>>>>> and instantiated when a new class member is constructed.
>>>>>
>>>>> In the ES proposal for class fields we mimic this type of behavior by 
>>>>> instantiating properties on the object when it's constructed, but there's 
>>>>> no runtime guarantee that this set of properties will remain the same.
>>>>>
>>>>> There's no reason not to put this in the constructor, and although 
>>>>> putting class fields on the prototype is debatably not the best idea, it 
>>>>> would be the only scenario where we get some kind of new helpful behavior 
>>>>> out of it.
>>>>>
>>>>> Ben
>>>>>
>>>>> Le sam. 25 août 2018 14 h 25, Augusto Moura <[email protected]> a 
>>>>> écrit :
>>>>>>
>>>>>> 24-08-2018 19:29, Aaron Gray <[email protected]>:
>>>>>>
>>>>>> >
>>>>>> > Yeah it does look like its badly "broken by design".
>>>>>> >
>>>>>>
>>>>>> Why this behaviour is broken? Every OOP language that I worked with
>>>>>> behaves de same way, and there's not many developers complaining about
>>>>>> it. If you want to use a property that might be overrided in a
>>>>>> subclasss you need to use a method and make the source of the data
>>>>>> more versatile (in Java and others similiar languages we have to
>>>>>> implement it using getter methods). Luckily Javascript doesn't need
>>>>>> getter and setters methods to make a property overridable because of
>>>>>> getter and setters descriptors, so we can workaround the first example
>>>>>> easily:
>>>>>>
>>>>>> ``` js
>>>>>> class Bar {
>>>>>>   bar = 'in bar';
>>>>>>
>>>>>>   constructor() {
>>>>>>     console.log(this.bar)
>>>>>>   }
>>>>>> }
>>>>>>
>>>>>> class Foo extends Bar {
>>>>>>   _initiedSuper = false;
>>>>>>   _bar = 'in foo';
>>>>>>
>>>>>>   constructor() {
>>>>>>     super();
>>>>>>     this._initiedSuper = true;
>>>>>>   }
>>>>>>
>>>>>>   get bar() {
>>>>>>     return this._bar;
>>>>>>   }
>>>>>>
>>>>>>   set bar(val) {
>>>>>>     if (this._initiedSuper) {
>>>>>>       this._bar = val;
>>>>>>     }
>>>>>>   }
>>>>>> }
>>>>>>
>>>>>> new Foo(); // will log 'in foo'
>>>>>> ```
>>>>>>
>>>>>> *I have to say the relaying that the super constructor will use the
>>>>>> bar property and workarounding it **is a bad practice** and should be
>>>>>> avoided at any costs. The contract with the super class constructor
>>>>>> should rely only on the super call, these situations just reveal bad
>>>>>> design choices in the super class. Logan Smyth example is the correct
>>>>>> answer to this problem*
>>>>>>
>>>>>>
>>>>>> 25-08-2018 01:28, Jordan Harband <[email protected]>:
>>>>>>
>>>>>> >
>>>>>> > Personally I think a design where the superclass relies on any part of 
>>>>>> > the
>>>>>> > subclass is "broken by design"; but certainly there's ways you can 
>>>>>> > achieve
>>>>>> > that.
>>>>>> >
>>>>>>
>>>>>> Of course is not broken. The super class has a contract with a
>>>>>> parametrized option, it can be used in subclasses or just in a
>>>>>> constructor call `new Base({ idAttribute: 'foo' })`, if it has a
>>>>>> default value for that is not a sub class concern. When refactoring
>>>>>> code adding defaults and "lifting" parameters are very common ~not
>>>>>> only on OOP~ and relying that the super class is using some property
>>>>>> in the constructor is the real "broken by design".
>>>>>> _______________________________________________
>>>>>> es-discuss mailing list
>>>>>> [email protected]
>>>>>> https://mail.mozilla.org/listinfo/es-discuss
>>>>>
>>>>> _______________________________________________
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