```
const x = nameof y
const y = 1;
```

`x` would have the value “y”. It would not matter if `y` were initialized or 
had yet been reached during execution. It does not deviate from the purpose of 
`let` or `const`, because you are not accessing the value of the identifier.

Also consider that this is legal ECMAScript in a module:

```
export { y }
const y = 1;
```

The binding for `y` exists within the same block scope, it just has not yet 
been initialized. Exporting it via `export { y }`, closing over it via `() => 
y`, or accessing it via `nameof y` would all be the same. In all three cases 
you are accessing the *binding* of `y`, not the *value* of `y`. Even in the `() 
=> y` case, you don’t access the *value* of `y` until you execute the function.

From: guest271314 <[email protected]>
Sent: Saturday, June 15, 2019 3:57 PM
To: Ron Buckton <[email protected]>
Cc: [email protected]
Subject: Re: Re: What do you think about a C# 6 like nameof() expression for

> Sorry, I meant to say “not entirely correct”.

You have not yet confirmed if in fact the expected output is referencing a 
variable declared using ```const``` on the current line _before_ initialization 
_on the next line_.

That example appears to deviate from the purpose and usage of ```const```, 
beyond the scope of ```nameof```, and if were implemented, a 
```ReferenceError``` should _not_ be thrown when a ```const``` variable that 
has yet to be initialized _on the next line_ is referred to _on the current 
line_?

Aside from that example, the code which essentially already implements 
```nameof``` should be able to be found in the code which implements 
```ReferenceError``` relevant to ```const```.

On Sat, Jun 15, 2019 at 10:47 PM Ron Buckton 
<[email protected]<mailto:[email protected]>> wrote:
Sorry, I meant to say “not entirely correct”.

From: Ron Buckton
Sent: Saturday, June 15, 2019 3:03 PM
To: guest271314 <[email protected]<mailto:[email protected]>>
Cc: [email protected]<mailto:[email protected]>
Subject: RE: Re: What do you think about a C# 6 like nameof() expression for

> At that point in the example code the identifer ```y``` does not exist.

That is not entirely incorrect. The identifier `y` exists, but its binding has 
not been initialized, otherwise you couldn’t refer to y in this case:

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