Can anyone tell me what's wrong with a really simple approach? Wherever you
are calling method(), just call methodWithAfter():
//in base class
methodWithAfter(){
method();
after()
}
What am I missing, guys?
On Fri, 19 Jul 2019 at 07:43, Michael Haufe <[email protected]> wrote:
> Revisiting this topic: why is the Template Method pattern not acceptable
> to accomplish this?
>
> <script>
> class Base {
> constructor() {
> this._beforeAction()
> this._action()
> this._afterAction()
> }
> _beforeAction(){
> console.log(`Base._beforeAction()`)
> }
> _action(){
> console.log(`Base._action()`)
> }
> _afterAction(){
> console.log(`Base._afterAction()`)
> }
> }
>
> class A extends Base {
> _action(){
> console.log(`A._action()`)
> }
> }
>
> let a = new A()
> // console reads:
> // > Base._beforeAction()
> // > A._action()
> // > Base._afterAction()
> </script>
>
> /Michael
> -----
>
> Monday, February 11, 2019 10:34 PM Michael Haufe <[email protected]>
> wrote:
>
> > You can use a Proxy in the base class:
> >
> > <script>
> > let handlerExample = {
> > get(target, prop) {
> > let feature = target[prop]
> > return feature instanceof Function ?
> > function () {
> > console.log('Before call');
> > let result = feature.apply(this, arguments)
> > console.log('After call');
> > return result
> > }
> > : feature
> > }
> > }
> >
> > class Base {
> > constructor() {
> > return new Proxy(this, handlerExample)
> > }
> > m1() { return "m1" }
> > }
> >
> > class Sub extends Base {
> > m1() { return `override ${super.m1()}` }
> > m2() { return `m2` }
> > }
> >
> > let base = new Base()
> > console.log(base.m1())
> >
> > let sub = new Sub()
> > console.log(sub.m1())
> > console.log(sub.m2())
> > </script>
> >
> > /Michael
>
>
> On Fri, Feb 8, 2019 at 1:22 AM #!/JoePea <[email protected]> wrote:
>
> > I many times find myself in cases where a base class wants to ensure
> that logic is always fired after the current method's execution, so that
> for example no matter in which order sub classes call the `super` method,
> the `super` method can still guarantee that logic fires after the whole
> stack of the same method in the class hierarchy.
>
> > So what I can do now is use `Promise.resolve().then(() => { ... })` to
> schedule that logic for later, that way all the invocations of a `foo`
> method along the class hierarchy have all fired. But this means that other
> code can also fire before the next microtask.
>
> > Is there some way to do it? If not, I wonder if some language feature
> for doing it would be possible?
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>
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