This is getting very reminiscent of my 'forwarding ternary' operator (or
whatever I called it) I suggested a couple of years ago. I believe you were
involved in the discussion, Andrea...!

```
const val = foo() ?!
  (x) => x.bar.baz :
  someFallbackValue;
```

On Sat, 7 Sep 2019, 10:17 Andrea Giammarchi, <[email protected]>
wrote:

> To better answer, let's start dropping any direct access and put a payload
> in the mix.
>
> As example, in the `foo()?.bar.baz` case, you might end up having `null`
> or `undefined`, as result, because `foo().bar` existed, but `bar.baz`
> didn't.
>
> In the `foo()?.bar?.baz` case, you might end up having `foo().bar`,
> because `bar.baz` didn't exist.
>
> But what if you are not interested in the whole chain, but only in a main
> specific point in such chain? In that case you would have `foo()?.bar.baz
> ?? foo()`, but you wouldn't know how to obtain that via `foo()?.bar?.baz ??
> foo()`, because the latest one might result into `foo().bar`.
>
> Moreover, in both cases you'll end up multiplying the payload at least *
> 2, while the mouse trap will work like this:
>
> ```js
> foo()<?.bar?.baz
> ```
>
> if either `foo().bar` or `bar.baz` don't exist, the returned result is
> `foo()`, and it's computed once. You don't care about `foo().bar` if
> `bar.baz` is not there, 'cause you want to retrieve `foo()` whenever you
> have a failure down the chain.
>
> Specially with DB operations, this is a very common case (abstraction
> layers all have somehow different nested objects with various info) and the
> specific info you want to know is usually attached at the top level bject,
> while crawling its sub properties either leads to the expected result or
> you're left clueless about the result, 'cause all info got lost in the
> chain.
>
> The `foo()<?.bar.baz` case is a bit different though, 'cause if
> `foo().bar` existed, there's no way to expect `foo()` as result, and if
> it's `bar` that you're after you can write instead `foo()?.bar<?.baz` so
> that if `baz` is not there, `bar` it is.
>
> This short-circuit the need for `??` in most cases, 'cause you already
> point at the desired result in the chain in case the result would be `null`
> or `undefined`.
>
> However, `??` itself doesn't provide any ability to reach any point in the
> previous chain that failed, so that once again, you find yourself crawling
> such chain as fallback, resulting potentially in multiple chains and
> repeated payloads.
>
> ```js
> // nested chains
> foo()?.bar.baz?.biz ?? foo()?.bar.baz ?? foo()?.bar;
>
> // mouse trap
> foo()?.bar<?.baz?.biz;
> ```
>
> Above example would prefer `foo().bar` if it exists, and if either
> `bar.baz` or `bar.baz.biz` returned `null` or `undefined`.
>
> I hope this clarifies further the intent, or the simplification, that such
> operator offers: it's a complementary hint for any optional chain, it
> doesn't have to be used, but when it does, it's visually semantic in its
> intent (at least to my eyes).
>
> Regards
>
>
>
>
> On Fri, Sep 6, 2019 at 11:20 PM Tab Atkins Jr. <[email protected]>
> wrote:
>
>> On Fri, Sep 6, 2019 at 8:04 AM Andrea Giammarchi
>> <[email protected]> wrote:
>> > Indeed I'm not super convinced myself about the "branching issue"
>> 'cause `const result = this?.is?.branching?.already` and all I am proposing
>> is to hint the syntax where to stop in case something else fails down the
>> line, as in `const result = this.?.is<?.branching?.too` to know that if any
>> other part is not reached, there is a certain point to keep going (which
>> is, example, checking that `result !== this`)
>>
>> Important distinction there is that ?. only "branches" between the
>> intended type and undefined, not between two arbitrary types. The
>> cognitive load between those two is significantly different.
>>
>> In particular, you can't *do* anything with undefined, so
>> `foo?.bar.baz` has pretty unambiguous semantics - you don't think you
>> might be accessing the .baz property of undefined, because that
>> clearly doesn't exist.
>>
>> That's not the case with mouse, where it's not clear, at least to me,
>> whether `foo<?.bar.baz` is doing `(foo.bar ? foo.bar : foo).baz` or
>> `foo.bar.baz ? foo.bar.baz : foo` or even `foo.bar ? foo.bar.baz :
>> foo`. All three seem at least somewhat reasonable, and definitely
>> *believable* as an interpretation!
>>
>> ~TJ
>>
> _______________________________________________
> es-discuss mailing list
> [email protected]
> https://mail.mozilla.org/listinfo/es-discuss
>
_______________________________________________
es-discuss mailing list
[email protected]
https://mail.mozilla.org/listinfo/es-discuss

Reply via email to