Why doesn't Function have something like apply that does the same as
in a new expression, i.e. allocate-init-and-apply? To put it another
way: given arguments in an array, I want to write:
F.thisThing(args) and have it mean the same as new F(args[0], args[1],
... args[n-1])
Or is what happens behind the veil of object creation detailed enough
that I can write a facsimile of it with apply? I guess something like:
var x = {};
x.prototype = F.prototype;
x = F.apply(x, args) || x;
But why force me to guess? No doubt I am wrong.
Dominic
On Mon, Mar 10, 2008 at 7:38 PM, Jon Zeppieri <[EMAIL PROTECTED]> wrote:
> On 3/10/08, Lars Hansen <[EMAIL PROTECTED]> wrote:
> > First draft of the spec for the Function class. Please comment.
> >
>
> Suggestion: deprecate the Function constructor and static invoke().
>
> Almost all of its uses are better handled by function expressions and,
> in those cases where eval() in required, one can use eval().
>
> -Jon
>
>
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