Re: [Ethereal-dev] PPP dissector bug

[Irfan Khan]

On Mon, Mar 10, 2003 at 08:15:22PM -0700, Irfan Khan wrote:
 

0x7e is escaped in PPP (preceded by 0x7d).
   

To be precise, 0x7e is escaped in PPP in HDLC-like framing.  However, at
least as I read the L2TP spec, the framing is supposed to be removed by
the time the packets are encapsulated in L2TP, so that a 0x7e is just a
0x7e.
 

Yes a 0x7e becomes a 0x7e 0x5e.  I see what you are saying a protocol 
with a protocol number 0x7e 0xkk would not work in this case.