Ha! This is good.
Unfortunately, I think they're all just a little broken. First off, if you protect $@, things won't work right. "$@" means all arguments inclusive, so all the arguments will be treated like one big one:
wget "http://a.com http://b.com";
This is not what you want.
wget "http://a.com"; "http://b.com";
is what you want. So, how to do that, or:
wget "http://a.com"; wget "http://b.com";
and even
wget "http://a.com/this is a link with spaces" wget "http://b.com";
Try this one:
while [ $# -ne 0 ]; do wget r -l1 -nc --no-parent -A.pk3 "${1}"; shift; done
Keep in mind that this only takes arguments when protected by the shell:
./myscript.sh "http://www.com/this is a link" "http://a.com"; "http://whatever.com/~!$ADSDF";
and it will fail in the case of ./myscript.sh http://www.com/this is a link
because it thinks of them all as individual arguments.
Mr O wrote:
This what I have: #!/bin/sh wget -r -l1 -nc --no-parent -A.pk3
This is what you want.
#!/bin/sh wget -r -l1 -nc --no-parent -A.pk3 "$@"
That will let you pull several sites in the same command.
./myget.sh http://site1/foo http://site2/bar http://site3/baz
If you're tired of typing "http://";, you could do this instead.
#!/bin/sh wget -r -l1 -nc --no-parent -A.pk3 "http://$1";
./myget.sh site1/foo ./myget.sh site2/bar ./myget.sh site3/baz
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