On 9/9/2025 9:57 PM, Alan Grayson wrote:


On Tuesday, September 9, 2025 at 5:18:14 PM UTC-6 Brent Meeker wrote:



    On 9/8/2025 8:45 PM, Alan Grayson wrote:


    On Monday, September 8, 2025 at 9:35:09 PM UTC-6 Brent Meeker wrote:



        On 9/8/2025 11:19 AM, Alan Grayson wrote:


        On Monday, September 8, 2025 at 5:06:36 AM UTC-6 John Clark
        wrote:

            On Mon, Sep 8, 2025 at 7:00 AM Alan Grayson
            <agrays...@gmail.com> wrote:

                /> I'm not sure the impossibility of absolute
                simultaneity solves the problem,/

            *
            *
            *Watch the video!If you follow what he does step-by-step
            you will see that he is right. It's not difficult. *


        *I'll definitely watch it, very soon, but a-priori the
        impossibility of absolute simultaneity can't solve the
        paradox because it's not its cause. Can you succinctly state
        the cause of the paradox? It's the application of time
        dilation in SR, under the mistaken assumption that the twins
        take symmetric paths; that their situations are symmetric.
        This results in the situation that when they meet and
        compare clock readings, each concludes the other is younger. *
        No that's wrong.  The stay at home twin has a clock that
        indicates a longer interval than the traveling twins clock. 
         They agree that the traveling twin is younger.

        Brent


    *Can't you understand English? I was stating the paradox and its
    cause. With an accurate analysis, the traveling twin is younger.
    Also, FWIW, for the traveling twin to return for the clock
    comparison, some acceleration is necessary, although it can be
    minimized if the comparison is done by fly-by. a AG *
    But notice that the acceleration is entirely incidental, as
    illustrated by the case in which Red and Blue each accelerates the
    same amount.  IT'S JUST GEOMETRY.  ONE PATH IS LONGER THAN THE OTHER.


*In the original statement of the "paradox', the traveling twin must accelerate to return so the clocks can be compared. Please explain how this can happen without acceleration. *
I've shown two different ways without acceleration and I've also shown the paradox with equal accelerations by both twins.  Why can't you just accept that it's geometry; that one path is longer than the other.



*You seem to defying basic physics if this is your claim. I don't deny that the original problem can be restated in a way which avoids acceleration, and IMO this is what you've done. *
But I've done more than that.  I've done it while maintaining exactly the same paradox.

Brent

*AG *


    Brent

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