On 10/1/2025 10:42 PM, Alan Grayson wrote:


On Wednesday, October 1, 2025 at 10:48:48 PM UTC-6 Brent Meeker wrote:



    On 10/1/2025 7:13 PM, Alan Grayson wrote:


    On Wednesday, October 1, 2025 at 6:11:55 PM UTC-6 Brent Meeker wrote:



        On 10/1/2025 6:38 AM, Alan Grayson wrote:


        On Wednesday, October 1, 2025 at 7:20:13 AM UTC-6 John Clark
        wrote:

            On Wed, Oct 1, 2025 at 8:29 AM Alan Grayson
            <agrays...@gmail.com> wrote:

                /> Have physicists in the last 120 years claimed
                that two paths of different lengths in spacetime
                which start and end at same events, have the same
                accelerations, except Brent in his diagram? AG/


            *In a word, yes. Two worldlines between the same events
            in spacetime can have different lengths even if both
            involve acceleration. And proper time is the length of
            your world line. But of course if they have identical
            acceleration histories then they are in the same
            worldline, not a different one.*


        You're writing nonsense. Brent has two worldlines with
        different lengths, claiming they have identical
        accelerations. AG
        And he included diagrams showing the accelerations had the
        same amplitudes and durations.  And that even was redundant. 
        From the diagram it is clear that Red and Blue had the same
        velocity at the initiation of their accelerations and they
        turned their velocity thru the same angle in each period of
        acceleration...hence one can infer mathematically that their
        (acceleration*duration) products were the same.

        Brent


    *That was your intention, but since the clock moving along the
    longer path, needs a greater turn if done in one acceleration, I
    don't think splitting the accelerations into two components
    solves your intention to make the accelerations of both paths
    equal. *
    What the hell does "solves you intention" mean.  The velocities
    are the same and the angle thru which they turn is the
    same...those are hypotheticals of the story.  It follows that the
    (acceleration*duration) are the same.


*"Solves your intention" means your model establishes, from your pov, that acceleration does not solve the TP problem. This is plain English. Why can't you understand it? AG*
*
*
*On the longer path, the further out it goes, the greater is the turn required, *
But that's simple false.  No matter how far away Red goes he only need to make a 180deg turn to return.  The four turns in the diagram are all 90deg turns in space.

Brent
*and hence, more acceleration. Drawing it in a way that makes the accelerations identical is impermissible if you're trying to prove the accelerations are identical. AG*

    *Recall that in the usual interpretation of the TP, where one
    twin is stationary and the other traveling, this situation is a
    limiting case of what you're doing in the diagram. *
    NO, IT IS THE SAME CASE.  In my diagram it is clear that Blue is
    stationary for the duration of Red's trip.  Are you going to claim
    that it matters whether Blue was stationary some other time??

*
*
*I never claimed it's the same case. You have two paths. One twin is stationary in the standard TP.  In the case we're discussing, both are moving. I just brought up the case of the standard TP to discuss one limiting case. Then I discussed the other limiting case where both are moving and the paths juxtaposed. Didn't you understand what I was doing? AG*

    *It tends to confirm that the accelerations are not identical in
    your more general case. The only real proof of your claim is
    mathematically. The fact that your diagram affirms your claim is,
    IMO, insufficient. AG*
    Which only shows how ignorant or unserious you are.

*No. What it shows is you're emotionally unqualified to consider yourself a teacher. Obviously, you don't have a clue what I am alleging. AG *


    Brent

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