On Wed, Dec 13, 2006 at 09:14:36AM -0000, William wrote:
>
> I think I'm following your reasoning here, this theorem could also be
> used to prove that any probability distribution for universes, which
> gives a lower or equal probability to a system with fewer information;
> must be wrong. Right ?

##
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Essentially that is the Occam razor theorem. Simpler universes have
higher probability.
>
> But in this case, could one not argue that there is only a small number
> (out of the total) of "higher" universes containing an SAS, and then
> rephrase the statement to "we are not being simulated by another SAS" ?
>
By "higher" I gather you mean more complex. But I think you are
implicitly assuming that a more complex universe is needed to simulate
this one, which I think is wrong. All that is needed is Turing
completeness, which even very simple universes have (for instance
Conway's Game of Life).
Cheers
PS - I'm off tomorrow for the annual family pilgrimage, so I'll be
rather quiet on this list for the next month.
----------------------------------------------------------------------------
A/Prof Russell Standish Phone 0425 253119 (mobile)
Mathematics
UNSW SYDNEY 2052 [EMAIL PROTECTED]
Australia http://www.hpcoders.com.au
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