-- On Mon, 1/25/10, Stephen Paul King <stephe...@charter.net> wrote: > Does not the mutual interfearence between the "copies" hace something to do > with a QM systems ability to compute exponensially more than a classical > system? If so, then reducing the number or density of copies would lead to an > attenuation in the computational power of the associated system. That is > clearly not a good thing!
Hi Stephen. In answer to your question, the first thing I must point out is that there is no evidence that the human brain can perform any quantum computing, and good reasons to think it can't - it's hard to isolate qbits from the environment. Also, even for a quantum computer, by 'copy' I don't think we just mean other parts of the wavefunction; we mean systems that perform the same computation. So in any case, if it's really 'copies' that we are reducing, and not limiting it in some other way, by definition there would be no change in the type or output of computation. However, the number of implementations would be reduced. An interesting question is whether conscious quantum computers would tend to observe the Born Rule as we do. I think they would, but it's not something that can be tested experimentally by us, because the only thing we would test is that our own Born Rule predicts what replies from them we tend to recieve. In most of our worlds they would agree that they see the Born Rule, but we'd have no way to test if that's true in most of their own worlds. > PS: I still would like to understand how the notion of measure or density is > considered. Perhaps you could ask a more specific question. Measure I thought I explained in the paper. By 'density' I'm not sure what you mean here. -- You received this message because you are subscribed to the Google Groups "Everything List" group. To post to this group, send email to everything-l...@googlegroups.com. To unsubscribe from this group, send email to everything-list+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/everything-list?hl=en.