On 23 Jul 2013, at 16:00, Jason Resch wrote:
When there are two polarizers A and C, which are rotated by 90
degrees to each other then no photons will pass through both
polarizers. However, if we insert polarizer B at a 45 degree offset
to A and C then 1/4 of the photons will make it through.
Now let's say we have two entangled photons travelling away from
each other. If we send photon #1 through polarizer A right before
photon #2 goes through polarizer B, right before photon #1 goes
through polarizer C, then if I understand entanglement correctly
that implies some of the time photon #1 will make it through
polarizer C. Is that correct?
Yes. Relatively to you.
To me it seems that must be incorrect, because it would enable super
In a single universe, it looks like there is such a communication, but
the math shows that you cannot use it to send information (like with
But if you look at this in the Everett picture, you can see that there
are no superluminal communications at all. By choosing some angle of
some polarizer, you determine the type of partitioning of the
multiverse you will stay in. May be you can do the computation
yourself, and you might be inspired by the computation that Steve
Price does in his "Everett FAQ".
By sending a continuous stream of entangled photons in opposite
directions and changing the orientation of B between 0 and 45
degrees, you could cause photons at C to stop with 100% or 75%
probability. This cannot be so then what is wrong with the above
assumptions of how the three polarizer experiment works with
I think that you are using implicitly the "uniqueness of outcome"
somewhere. Not much time to do the details for now, but I might do it
later if nobody does it. But you can do it, also, as this needs only a
minimal amount of QM. Of course this will not prove that Everett is
always "local" in general. For this you can take a look on some paper
by Tipler, or more rigorous one by Deutsch and Hayden, but even this
is criticized by some physicists.
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