# Re: Spacetime is (nonphysical, platonic) mind

```2013/11/11 meekerdb <meeke...@verizon.net>

>  On 11/11/2013 12:11 AM, LizR wrote:
>
>  On 11 November 2013 18:18, meekerdb <meeke...@verizon.net> wrote:
>
>>   On 11/10/2013 5:59 PM, LizR wrote:
>>
>> On 11 November 2013 13:53, meekerdb <meeke...@verizon.net> wrote:
>>
>>>  On 11/10/2013 3:54 PM, Quentin Anciaux wrote:
>>>
>>>
>>>  Sure, but the thing is that *you have to*, and asking such question at
>>> that stage is very likely... you can't be 10⁵ years old before having been
>>> 1 year old... it's simply nonsense.
>>>
>>>
>>>  So you're falling back on the all-purpose 'everything' answer; whatever
>>> you observe is one of everything and that why everything is consistent with
>>> it - like why I'm not a Chinaman?
>>>
>>>  There isn't any falling back here that I can see. It seems quite
>> reasonable to say you have to pass through your birthdays in ascending
>> order. I can't see why that is problematic / contraversial?
>>
>>
>>  Sure, but if I live infinitely long I will have almost all my
>> experiences older than 75.  So when I note that I'm not that old and that
>> seems improbable, it's not an answer to say, "Well, less than 75 is an age
>> you must be sometime."  Jason at least had an answer, although I don't
>>
>
>  I didn't say "75 is an age you must be sometime" - I said "75 is an age
> you must be before you can be 76". You can only reach age N by traversing
> all lower ages first. You can't use a self-sampling argument to show that
> you shouldn't be your current age if you *have* to pass through that age
> before you can experience any greater ages.
>
>
> I don't see the relevance of that.  I had to pass through being 5 too.
> Suppose you are shown a machine and told that it is counting to infinity,
> i.e. indefinitely.  You're asked to guess what number it's on. Would you be
> surprised if it were on 75?
>```
```
It depends how fast it counts and when it was built... If the machine was
built "recently", and it added 1 every year... no I wouldn't.

Quentin

>
> Brent
>
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