Jason, Come on Jason. Of course not. You have to have EQUAL amounts of acceleration to produce the same effect. But doesn't matter where in space it is.

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Edgar On Friday, January 3, 2014 10:24:26 AM UTC-5, Jason wrote: > > > > > On Fri, Jan 3, 2014 at 10:19 AM, Edgar L. Owen <edga...@att.net<javascript:> > > wrote: > >> Jason, >> >> If the acceleration is the same, the slowing of clock time will be the >> same... Doesn't matter where it is. Or equivalently (by the principle of >> equivalence) it could be standing 'still' in a strong gravitational field. >> >> Edgar >> >> > > Okay but this is certainly not what happens. If you spent 4 minutes > accelerating and came back, there would not be a 4 year age difference when > Pam returned. > > Jason > > > >> >> >> >> On Friday, January 3, 2014 10:06:08 AM UTC-5, Jason wrote: >>> >>> >>> >>> >>> On Fri, Jan 3, 2014 at 9:21 AM, Edgar L. Owen <edga...@att.net> wrote: >>> >>>> Lliz, Brent and Jason, >>>> >>>> Actually Liz is correct here, by GR it is the acceleration. That is the >>>> physical cause of the clock time differences of the twins. >>>> >>> >>> In my experiment, lets say the acceleration lats for a total of 4 >>> minutes: one minute to accelerate up to 0.8 c, one minute to slow down at >>> Proxima Centauri, one minute to accelerate back up to 0.8 c toward Earth, >>> and a final minute to accelerate down to back at Earth. >>> >>> If the accelerations alone account for the clock discrepancies, then >>> there would be no need to go to Proxima Centauri at all. Pam could spend 4 >>> minutes whizzing around the solar system and get in all the same >>> accelerations. >>> >>> Is this what you are saying? >>> >>> Jason >>> >>> >>>> It is true the effects can also be analyzed just by spacetime paths as >>>> others have suggested, but it is actually the acceleration (or equivalent >>>> gravitational field which is in effect an acceleration) which actually >>>> physically produces the clock time differences when the twins meet up >>>> again. >>>> >>>> Edgar >>>> >>>> >>>> On Friday, January 3, 2014 1:27:55 AM UTC-5, Liz R wrote: >>>>> >>>>> On 3 January 2014 17:30, meekerdb <meek...@verizon.net> wrote: >>>>> >>>>>> On 1/2/2014 8:00 PM, LizR wrote: >>>>>> >>>>>> On 3 January 2014 15:52, Jason Resch <jason...@gmail.com> wrote: >>>>>> >>>>>> On Thu, Jan 2, 2014 at 9:31 PM, LizR <liz...@gmail.com> wrote: >>>>>>> >>>>>>>> Jason, >>>>>>>> >>>>>>>> You may be missing the fact that the acceleration of the space >>>>>>>> traveller is what causes the twin paradox. >>>>>>>> >>>>>>> >>>>>>> I would say it is not so much the acceleration that explains the >>>>>>> paradox, but the fact that no matter how you rotate the paths, you >>>>>>> always >>>>>>> see a kink in the path Pam takes. >>>>>>> >>>>>> >>>>>> May I venture to suggest this is the same thing :-) >>>>>> >>>>>> >>>>>> That's not exactly wrong - but it tends to make it confusing. It's >>>>>> like saying a road from A to B is longer than as-the-crow-flies because >>>>>> of >>>>>> its curves. Yeah, that's true; but if you want to calculate how much >>>>>> longer you see that the rate of excess distance is proportional to the >>>>>> first integral of the curvature and so the total excess is the second >>>>>> integral of the curvature - which is just the distance. So it boils >>>>>> down >>>>>> to unstraight lines are longer than straight lines. All the specific >>>>>> details of acceleration get integrated out so it's easy to see that a >>>>>> broken line (infinite accelerations) is just longer. Or in spacetime, >>>>>> unstraight worldlines are shorter than straight ones. To phrase it in >>>>>> terms of acceleration misleads people into thinking about the stressful >>>>>> effects of acceleration and how that could affect a clock,... >>>>>> >>>>>> I bow to your superior knowledge. I wasn't thinking about the aging >>>>> effects of acceleration (as in the Heinlein story where they have to fly >>>>> to >>>>> Pluto at 3G) but just the fact that the course changes are the only way >>>>> the >>>>> twin paradox can be enacted - that is to say, it's what breaks the >>>>> symmetry >>>>> that otherwise exists between one ref frame's measurements and another's. >>>>> >>>>> -- >>>> You received this message because you are subscribed to the Google >>>> Groups "Everything List" group. >>>> To unsubscribe from this group and stop receiving emails from it, send >>>> an email to everything-li...@googlegroups.com. >>>> To post to this group, send email to everyth...@googlegroups.com. >>>> >>>> Visit this group at http://groups.google.com/group/everything-list. >>>> For more options, visit https://groups.google.com/groups/opt_out. >>>> >>> >>> -- >> You received this message because you are subscribed to the Google Groups >> "Everything List" group. >> To unsubscribe from this group and stop receiving emails from it, send an >> email to everything-li...@googlegroups.com <javascript:>. >> To post to this group, send email to everyth...@googlegroups.com<javascript:> >> . >> Visit this group at http://groups.google.com/group/everything-list. >> For more options, visit https://groups.google.com/groups/opt_out. >> > > -- You received this message because you are subscribed to the Google Groups "Everything List" group. 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