The average kinetic energy of an air molecule is zero, I imagine, because
they're all travelling in different directions and cancel out? Or doesn't
it work like that?

On 21 November 2014 13:09, meekerdb <[email protected]> wrote:

>  On 11/20/2014 3:57 PM, George wrote:
>
>  Thanks Bruno, Liz and Richard for your responses.
>
>  The topic is extremely controversial… It took me a few months of
> sleepless nights to come to term with these ideas…. but let reason prevail.
> I am looking forward to an open and rational discussion… a background in
> statistical thermodynamics would be helpful.
>
>  Bruno, you may not be able to download my pdf file because your Adobe
> Reader is not up to date. If you wish I could simply attach these files to
> my email. Please let me know. You asked me to summarize my post. The best
> way is with pictures taken from my paper#2.
> https://sites.google.com/a/entropicpower.com/entropicpower-com/Thermoelectric_Adiabatic_Effects_Due_to_Non-Maxwellian_Carrier_Distribution.pdf?attredirects=0&d=1
> (Currently under review)
>
>  Figure 7 shows what happens to the energy distribution of a Maxwellian
> gas (e.g. air) as molecules rise from ground level (red) to a given
> altitude (blue). Kinetic energy is converted to potential energy and the
> distribution shifts to the left.
>
>
> Am I correctly interpreting this curve as showing that the kinetic energy
> probability density function is an exponential; so that the most probable
> kinetic energy for an air molecule is zero??  Why isn't it the
> Maxwell-Boltzmann distribution?
>
> Brent
>
>
>  However when the distribution is renormalized as shown in Figure 8, the
> original distribution is recovered, implying that the gas is isothermal
> with elevation. The Second Law is upheld and Loschmidt is proven wrong…..
> but only with respect to Maxwellian gases.
>
>  Now see what happens when a Fermi-Dirac gas (carriers in a
> semiconductor) is subjected to a force field as shown in Figure 9. The
> distribution is shifted to the left as elevation increases. However,
> renormalization does not recover the original distribution because it is
> not exponential. The lower elevation has a higher temperature than the
> higher elevation. The Second Law is broken. This effect can only be
> observed in high quality thermoelectric materials (Caltech experiment).
>
>  I have made this calculator program and a simulator publicly available
> at my web site.
>
>  *Figure. 7.* Un-normalized Maxwell distribution at ground (red/thick)
> and at non-zero elevation (blue/thin) showing a shift to a lower kinetic
> energy, a drop in density and a drop in temperature.
>
> *Figure. 8.* Renormalized shifted Maxwell distribution at non-zero
> elevation (blue/thin) is identical to original non-shifted distribution at
> ground level (red/thick).
>
>  *Figure. 11.* Un-normalized Fermi-Dirac distribution at ground
> (red/thick) and non-zero elevation (blue/thin) showing drop in density and
> drop in temperature.
>
> *Figure. 12.* Renormalized Fermi-Dirac distributions at ground level
> (red/thick) and at elevation (blue/thin) are different. Elevation lowers
> energy and temperature of gas.
>
>
>
> Please look on the right of the pictures for the temperatures at the
> ceiling and at the floor.
>
> George Levy
>
>
>
>
>  --
> You received this message because you are subscribed to the Google Groups
> "Everything List" group.
> To unsubscribe from this group and stop receiving emails from it, send an
> email to [email protected].
> To post to this group, send email to [email protected].
> Visit this group at http://groups.google.com/group/everything-list.
> For more options, visit https://groups.google.com/d/optout.
>

-- 
You received this message because you are subscribed to the Google Groups 
"Everything List" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to [email protected].
To post to this group, send email to [email protected].
Visit this group at http://groups.google.com/group/everything-list.
For more options, visit https://groups.google.com/d/optout.

Reply via email to