2015-06-10 15:13 GMT+02:00 Bruce Kellett <bhkell...@optusnet.com.au>:

> Quentin Anciaux wrote:
>
>> 2015-06-10 14:11 GMT+02:00 Bruce Kellett <bhkell...@optusnet.com.au
>>     Quentin Anciaux wrote:
>>
>>         2015-06-10 13:40 GMT+02:00 Bruce Kellett
>>         <bhkell...@optusnet.com.au <mailto:bhkell...@optusnet.com.au>
>>         Quentin Anciaux wrote:
>>
>>                 Then the computation will be in the mapping which is the
>>                 interpreter... the rock itself is missing the machine
>>                 interpreting the state and relating all the sequence of
>>         states
>>                 of the rock... The rock and the interpreter is a
>>         computation,
>>                 the rock alone is not.
>>
>>             What is the interpreter in Platonia?
>>
>>         The transition function relating the states.
>>
>>         A computation is not a sequence of states, it is a sequence of
>>         states and the relation between them.
>>
>>     The relation between them is given by the sequence order. You are
>>     the one who 'interprets' that sequence, gives it meaning.
>>
>> So a computer computing without us, is not computing....
>> The mapping is what makes the interpretation. A computation is a sequence
>> of state + a transition table relating the states.
>>
>> As you can map the rock states with an adhoc mapping to any computations,
>> it doesn't mean the rock computes everything, it just means the rock states
>> are not enough, you forget the mapping ie: the interpreter. The rock on
>> itself could compute anything, but relatively to you, it can compute
>> meaningfully only if you have the correct mapping... and if to produce such
>> a mapping that would make sense relatively to you, it asks you to do the
>> computation you want to map to the rock states... in what sense can you say
>> the rock is computing relatively to you in any meaningful sense ?
>>
>
> A computation can be regarded as a mapping between inputs and outputs. A
> Turing machine has a transition table relating the states -- that has to be
> provided to define the machine, as you say. You can do this with the rock,
> you map each rock state to the necessary computational state, and that
> mapping makes the interpretation in the same way as for any other computer.


That's what I said... you need the mapping and the rock... the rock alone
is not sufficient...

So instead of repeating what I said... in what sense the rock *alone* is
computing anything relevant relatively to you without the mapping ?

Quentin


>
>
> Bruce
>
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