Hi Bruno,

Thanks for your answer. It is indeed still not entirely clear to me.

On the one hand you wrote "It does not dovetail on non computable 
functions, which have no algorithm". On the other hand you wrote:"It 
dovetails because, indeed, some program will not stop". But a program that 
doesn't stop, isn't that precisely an uncomputable function? So the UD does 
dovetail uncomputabe functions, but obviously without ever reaching the 
output?

Ciao,
Peter

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