On Sat, Jan 5, 2019 at 7:15 PM Brent Meeker <[email protected]> wrote:

>
>
> On 1/5/2019 4:56 PM, [email protected] wrote:
>
>
>
> On Sunday, January 6, 2019 at 12:13:16 AM UTC, Brent wrote:
>>
>>
>>
>> On 1/5/2019 1:28 PM, [email protected] wrote:
>>
>> The relation is provided by the metric.  If you choose different
>>> coordinate systems (e.g. cylindrical or spherical or whatever) then there
>>> is different metric tensor.  So the integral along the path of g_ab dx^a
>>> dx^b is the same.
>>>
>>> Brent
>>>
>>
>> *I assume you're showing why the proper time along a given path is the
>> same for all observers, and this has nothing to do with coordinate time
>> being unrelated to proper time. AG *
>>
>>
>> Coordinate time between events A and B is just delta(x^0) = x^0(B) -
>> x^0(A).  Just like the longitudinal distance between LA and NY is
>> Long(LA)-Long(NY).  But the driving distance between LA and NY depends on
>> the path you take and is an integral along that path which includes changes
>> in latitude:
>>
>>     S^2 = INT_path g_ab dx^a dx^b = INT_path [ dlong*dlong*cos^2(lat) +
>> dlat*dlat]
>>
>> Notice the cos^2 factor because the space isn't  flat.
>>
>> So in GR coordinate time is related to proper time; it contributes a term
>> in accordance with the metric that describes the curvature of the
>> spacetime.  But there are other terms from the spatial coordinates and even
>> cross terms and the terms are weighted by the metric factors that describe
>> the shape of the space.
>>
>> Brent
>>
>
> *I think you mean that coordinate time is related to proper time as a path
> is traversed, *
>
>
> Right.  They are related, but not in a simple way.  Each increment of
> coordinate time along the paths contributes to the increment of proper
> time, but it is only one term of several.
>

I recommend Relativity Visualized:

https://www.amazon.com/Relativity-Visualized-Lewis-Carroll-Epstein/dp/093521805X

Jason

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