On Friday, January 11, 2019 at 11:08:42 AM UTC, Bruno Marchal wrote: > > > On 11 Jan 2019, at 11:02, agrays...@gmail.com <javascript:> wrote: > > If probability values are always positive and between 0 and 1, how does > one get destructive interference, or constructive interfering probability > values within the acceptable range? Brent once answered this question but I > have completely forgotten the answer. AG > > > > The “whole problem of QM” is there. The coefficients of the terms in the > superposition are the “amplitude of probability”, and they can be negative. > The probability is given by the square of the amplitude of probability. As > long as we don’t make any observation, the wave acts like a wave, and the > amplitudes can be added or subtracted. To get the probability for the > measurement result on phi, we take the square of the amplitude (in the base > corresponding to what we want to measure). >

*OK, but for positive amplitudes which are added, what guarantees that using Born's rule the result remains less than or equal to 1? AG * > > With Everett (non collapse), measurement is only self-entanglement. > Normally the Born rule should be justified from this, and some > justification exists, either based on frequency-operator (like Graham, > Preskill, and others) or by using Gleason theorem, etc. > > Note that I do not claim that Everett formulation of QM solves all > conceptual problems of QM. But mechanism might and should. The psi wave > correspond to a description of a first person plural reality in a context > of many computations, like mechanism justifies, except that the price is > the needed to get the waves from the logic of the measure one observable > (provable, true and consistent). That makes mechanism testable, and QM > confirms it, but there are many arithmetical-physics proposition which > needs to still be tested. > > Bruno > > > > > > -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to everything-li...@googlegroups.com <javascript:>. > To post to this group, send email to everyth...@googlegroups.com > <javascript:>. > Visit this group at https://groups.google.com/group/everything-list. > For more options, visit https://groups.google.com/d/optout. > > > -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to everything-list+unsubscr...@googlegroups.com. To post to this group, send email to everything-list@googlegroups.com. Visit this group at https://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/d/optout.