On Tue, Mar 5, 2019 at 2:03 PM Russell Standish <li...@hpcoders.com.au>
wrote:

> On Tue, Mar 05, 2019 at 12:06:00PM +1100, Bruce Kellett wrote:
> >
> > My problem with your idea that the function: "(n-1)+1" is a valid
> computational
> > algorithm for n is that it makes all real numbers also computable, but
> the
> > notion of Turing computability applies only to the integers. We do not
> want a
> > definition of 'computable', that makes all reals computable.
>
> You cannot represent n as a finite string for an arbitrary real number
> n. But you can for an arbitrary integer n.
>

Sure. But that was not part of your definition of a 'computation'. The
algorithm f(x): (r-1)+1 works for all reals r as well as for finite strings
n.

Bruce

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