> On 5 Aug 2019, at 15:12, Bruce Kellett <[email protected]> wrote:
> 
> On Mon, Aug 5, 2019 at 10:37 PM Bruno Marchal <[email protected] 
> <mailto:[email protected]>> wrote:
> On 5 Aug 2019, at 14:13, Bruce Kellett <[email protected] 
> <mailto:[email protected]>> wrote:
>> On Mon, Aug 5, 2019 at 6:07 PM Bruno Marchal <[email protected] 
>> <mailto:[email protected]>> wrote:
>> On 5 Aug 2019, at 03:27, Bruce Kellett <[email protected] 
>> <mailto:[email protected]>> wrote:
>>> On Sat, Aug 3, 2019 at 10:52 AM Jason Resch <[email protected] 
>>> <mailto:[email protected]>> wrote:
>>> On Fri, Aug 2, 2019 at 7:33 PM 'Brent Meeker' via Everything List 
>>> <[email protected] 
>>> <mailto:[email protected]>> wrote:
>>> On 8/2/2019 5:12 PM, Jason Resch wrote:
>>>> On Fri, Aug 2, 2019 at 6:51 PM 'Brent Meeker' via Everything List 
>>>> <[email protected] 
>>>> <mailto:[email protected]>> wrote:
>>> 
>>> Wherever it happens, it's one world.  Worlds are things things that are 
>>> orthogonal on to one another so that's why they're separate.  I don't know 
>>> what Deutsch believes.
>>> 
>>>>> In any case, you have still managed to avoid the question of the reality 
>>>>> of the 10^1000 intermediate computational states.  I won't press for an 
>>>>> answer if you don't have one.
>>>> 
>>>> I already gave the answer.  There is only one intermediate state.  It just 
>>>> happens to have lots of components in the basis you used to express it.
>>>> 
>>>> And each of those components represents a trace of a computation performed 
>>>> on one of the many possible values of the input qubits, do they not?
>>> 
>>> That's one way of representing them.  Just as citing the Fourier components 
>>> of a firecracker going off shows the many components of the sound.
>>> 
>>> That would be a convincing counterpoint, except here this "way of looking 
>>> at the many components" performs a computation that would not otherwise be 
>>> possible if all the atoms of the universe were mustered to perform the 
>>> computation.
>>> 
>>> The fact is that it is possible. The 2^n dimensions of the Hilbert space 
>>> for n qbits is ample space for the computations. The trouble with looking 
>>> to parallel worlds to do the computations is that there are an uncountable 
>>> infinity of possible bases for the Hilbert space. What picks out just one 
>>> base to represent all these parallel worlds? That is the real problem. You 
>>> are ignoring the basis problem, just as Deutsch does. You naively assume 
>>> that the computational base that you used to set up you quantum computer in 
>>> the first instance is the only possible basis in which to view it. If you 
>>> take the view that the single ray in Hilbert space represents all that is 
>>> possible to know about the QC, and that computations are nothing more than 
>>> rotations of this state ray in the space, then all these silly notions of 
>>> parallel worlds evaporate.
>> 
>> But then the interference between different branch of the universal ray, 
>> whatever base is used to describe it, will disappear.
>> 
>> No they won't. […] The rotations in this space cause exactly the necessary 
>> interferences. 
> 
> It is a functional space, the ray describes all relative histories, and in 
> the case of an observer looking a a superposition, the ray describes the 
> observer being superposed itself. Shor algorithm exploits this.
> 
> That is a really weird thing to say. The ray in Hilbert space is a concise 
> description over the basis vectors. Whatever you do in some basis is 
> reflected exactly in the ray representing the state. Conversely, whenever the 
> state vector is rotated, the representation in terms of the basis vectors is 
> changed correspondingly. They are not two distinct things. The point of 
> thinking in terms of the state vector is that this is independent of the base 
> chosen, so is a more objective way of looking at things.
> 
> Think of a simple example. In general relativity we have the static spacetime 
> given by Schwarzschild solution which describes a black hole. In the standard 
> Schwarzschild metric, there is a 1/(r - 2M) term, so it appears that there is 
> a singularity at the horizon (r = 2M). Eventually it was realised that this 
> is merely an artefact of the coordinate system -- the horizon is not really 
> singular, as can be shown by going to Kruskal or Eddington-Finkelstein 
> coordinates, which are both smooth at the horizon. Working in a particular 
> coordinate system (or set of basis states) is always fraught with ambiguity 
> (the 'preferred basis' problem), so the actual situation is best represented 
> by the state vector itself.
> 
> The thing about the Hilbert space vector describing the quantum computer is 
> that there is no observer involved. Since, in order to maintain coherence, 
> there cannot be any external observer. So it is just meaningless to claim 
> that "in the case of an observer looking a a superposition, the ray describes 
> the observer being superposed itself.”.

Maybe in some dualist theory of mind. I am just using the idea that O(a+b) = Oa 
+ Ob, where O is an observer not interacting with a superposition state. 

In that state, O has still the choice to look at this in the {a, b} base, or in 
the {a+b, a-b} base. In the first, the universal ray will describe ((O seeing 
a) a + (O seing b) b) (well normalised), 

Bruno







> 
> Bruce
> 
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