On Thursday, May 5, 2022 at 9:05:47 PM UTC-6 meeke...@gmail.com wrote:
> > > On 5/5/2022 6:04 PM, Bruce Kellett wrote: > > On Fri, May 6, 2022 at 10:45 AM Brent Meeker <meeke...@gmail.com> wrote: > >> If the mass-energy of the Sun is halved, then for the Earth to continue >> in the same orbital path, it's mass-energy must also be halved. The >> period, a year, will go up by a factor of sqrt(2). Will the SI definition >> of the second also go up by sqrt(2)? I think so. But if the Earth is >> slower in the same orbit, the measurements of the speed of light by stellar >> aberration will change. >> > > The problem I see is that orbital mechanics depend on the product of the > masses, not the ratio, so if the energy (and masses) halve, the orbits must > change. For example, the energy of the earth in orbit is the sum of the > gravitational and potential energies: > > E_T = KE +PE = I/2 mv^2 - GMm/r = GMm/(2r) - GMm/r = -GMm/(2r), > > where M is the mass of the sun, m is the mass of the earth, and r the > earth-sun distance. We note that the total energy is negative. If the total > energy is to halve, the radius must change since Mm/(2r) is divided by 4, > not 2. In other words, the radius of the orbit must also halve. If the KE > simply halves, the velocity will remain the same. But if the orbit changes, > the velocity must change also. > > > To a good approximation the mass of the Earth doesn't matter. Whatever > it's mass, it can continue in the same radius orbit if the Sun's mass is > halved and it's speed is reduced by a factor of 1/sqrt(2). There's more > than one way to halve the energy and you're trying do it changing r and > keeping v the same...which would certainly be noticeable to move closer to > the Sun. The way I see it is to keep the same orbital path at a lower > speed...which is measureable by the change in stellar abberation, event if > atomic clocks tick slower because of the energy change. > > > > The problems are magnified when we consider the potential energy of a mass > lifted from the surface of the earth: > PE = mgh. Now g = GM/(r^2), so it halves along with the mass m. So mgh is > reduced by a factor of 4 unless the height doubles in order for the PE to > change only by a factor of two. I think these effects would be very > noticeable, so the idea that one can halve the energy in a branch without > causing any changes within the branch is just a nonsense. > > The idea that the SI definition of the second will also change to > compensate other changes is as silly a notion as one could imagine. > > > It's determined by the energy difference of two levels of the cesium > atom. Why wouldn't it change? > > Brent > Thanks for these replies. I intuited that Clark's scenario must be wrong since after not too many splits, gravity is gone and so will closed orbits. AG -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to everything-list+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/everything-list/3e06266f-643f-42dc-9098-11287cbd641cn%40googlegroups.com.