On 9/2/2024 9:06 PM, Alan Grayson wrote:
On Monday, September 2, 2024 at 7:58:04 PM UTC-6 Brent Meeker wrote:
I should think it was obvious that the metric tensor, M, at a
point g*Mg gives the length of g.
It's not obvious and I don't see how it's relevant. At each point the
metric tensor can be evaluated on an uncountable set of pairs of
vectors. So which pair does one choose? AG
Don't pick a pair. Pick one and it's conjugate.
Brent
I generally ignore these questions because you're asking questions
that take some exposition which is found in any text book and many
online sites. I also recommend "Relativity Demystified" by David
McMahon.
TY for the reference. I'll check if it has the issue I need
addressing. It's not on any of the sites I checked, so far. AG
Bretn
On 9/2/2024 5:25 PM, Alan Grayson wrote:
Brent; do me a small favor. If you are unable to answer my
question, just say so. OK? AG
On Saturday, August 31, 2024 at 8:48:13 PM UTC-6 Alan Grayson wrote:
You seem to know a lot about relativity, so please explain
how the metric tensor can be defined unambiguously at some
point P on the underlying manifold, spacetime, if there is an
uncountable set of pairs on a vector space on the tangent
space at some point P on which the metric tensor is defined
(as a bilinear function which maps to the real numbers.) TY, AG
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