I know how they're defined but I never used them. AG

On Thursday, September 5, 2024 at 5:26:36 PM UTC-6 Brent Meeker wrote:

> Ever use cylindrical coordinates?
>
> Brent
>
>
>
> On 9/5/2024 2:07 PM, Alan Grayson wrote:
>
> Since the metric tensor is defined on the* flat *tangent space, will its 
> matrix representation always be diagonal? TY, AG
>
> On Thursday, September 5, 2024 at 12:35:03 PM UTC-6 Brent Meeker wrote:
>
>> If  you change coordinate systems the vectors and tensors transform in 
>> such a way that the physics is unchanged.  That's the defining property of 
>> vectors and tensors and why they are not just the arrays used to represent 
>> them.
>>
>> Brent
>>
>>
>>
>> On 9/4/2024 10:42 PM, Alan Grayson wrote:
>>
>> How is the foregoing consistent with the statement that tensors are 
>> independent of coordinate systems? TY, AG
>>
>> On Wednesday, September 4, 2024 at 10:39:33 PM UTC-6 Alan Grayson wrote:
>>
>>> No; you never posted any page numbers in your reference. Had you done 
>>> that, I would have immediately studied your specific reference. But I was 
>>> about to post something like what you wrote; namely, that *solving* for 
>>> the metric tensor *MEANS* solving for the 16 components defining its 
>>> function, given a stress-energy tensor and a coordinate system. The form of 
>>> the components must depend on the coordinates. And given a coordinate 
>>> system, the components will vary depending on location in spacetime, and 
>>> this is what's meant by the "metric tensor field". I thought the "field" 
>>> refers to a *unique* *real numbe*r at each point in spacetime, but it 
>>> must refer to the components of the matrix representing the tensor.  Wiki's 
>>> definition seems misleading since it states that the metric tensor is a 
>>> bilinear function of two vectors on the tangent plane. Those vectors are 
>>> its arguments, but sort-of misleading. Is there anything in the foregoing 
>>> that I got wrong? AG 
>>> On Wednesday, September 4, 2024 at 8:09:07 PM UTC-6 Brent Meeker wrote:
>>>
>>>> The metric field is the set of metric tensors, one at each point.  It's 
>>>> not some vector lengths.
>>>>
>>>> When are you gonna read "Relativity DeMystifie".  I told you the page 
>>>> numbers and you can look up more in the index.
>>>>
>>>> Brent
>>>>
>>>>
>>>>
>>>> On 9/4/2024 5:59 PM, Alan Grayson wrote:
>>>>
>>>> But my point is therefore that the metric tensor field is ambiguous !
>>>>
>>>> On Wednesday, September 4, 2024 at 6:40:38 PM UTC-6 Brent Meeker wrote:
>>>>
>>>>> It explains this "...and yields *different *real values for most 
>>>>> different pairs."
>>>>>
>>>>> Brent
>>>>>
>>>>>
>>>>>
>>>>> On 9/4/2024 1:03 PM, Alan Grayson wrote:
>>>>>
>>>>> and yields *different *real values for most different pairs.
>>>>>
>>>>>
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