On Mon, Nov 04, 2024 at 10:12:39PM -0800, Brent Meeker wrote:
> 
> 
> 
> On 11/4/2024 9:47 PM, Alan Grayson wrote:
> 
> 
>     On an unrelated issue, I recall your mention that wrt the S. Cat thought
>     experiment, there is no
>     operator which has Alive and Dead as eigenvalues. IMO, this implies that
>     the S. Cat thought
>     experiment just doesn't fit into any quantum thought experiment. I then
>     realized that the P 
>     operator for momentum must have a real value for its eigenvalues since 
> it's
>     Hermitian, BUT
>     how can a real value represent momentum, which is a vector?  TY, AG
> 
> The eigenvector would be momentum.
> 

Sorry Brent - the measured momentum values are still eigenvalues.

Pick 3 orthogonal directions to measure the momentum, say x, y and z.

Then the momentum operators are -iℏ∂/∂x, -iℏ∂/∂y and -iℏ∂/∂z, and the 3 
eigenvalues are the 3 components of momentum.

One could also write it in vector form iℏ∇, in which case the operator
has a vector-valued eigenvalue.


-- 

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Dr Russell Standish                    Phone 0425 253119 (mobile)
Principal, High Performance Coders     [email protected]
                      http://www.hpcoders.com.au
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