On 1/15/2025 4:55 PM, Alan Grayson wrote:


On Wednesday, January 15, 2025 at 5:15:35 PM UTC-7 Brent Meeker wrote:




    On 1/15/2025 1:39 PM, Russell Standish wrote:
    What you are talking about is known as the preferred basis
    problem. This has been discussed on this list before. My own take
    on this is that you can't ignore the observer. In any physical
    situation, an observer chooses some measurement apparatus
    (thereafter you can sweep the observer under the carpet, and
    focus on the measurement apparatus). The measurement apparatus
    entangled with the system under question has the dynamics that
    tensor product of measuring apparatus state with that of the
    system evolves to be diagonal in some basis, aka "einselection".
    And that is the origin of the preferred basis. In the multiverse,
    there will also be other observers choosing different apparati eg
    ones that select a complementary basis (eg momentum where the
    first chooses to measure position). These will have a different
    set of preferred basis. There is only a problem if you try to
    ignore the existence of observers and measuring devices. Cheers
    On Wed, Jan 15, 2025 at 11:58:33AM -0800, Alan Grayson wrote:
    It's easy to show that a Superposition does NOT imply that a
    system represented by a linear sum of a pure set of basis
    vectors, is in all of those states simultaneusly.This follows
    from the fact that the WF is an element of a vector space, a
    Hilbert space, and in vector spaces there is no unique set of
    basis vectors. IOW, any set of basis vectors can represent the
    WF of a system, and if we claim the system is in all states of
    some superposition, it must also be in all states of any other
superposition.
    If it's in a pure state then that is single vector in Hilbert
    space.  So there is a basis
    that includes that vector and then the state has a single
    component in that basis.
    Of course there is no way to measure in that basis without already
    knowing what
    what it is.

    Brent

 Generally speaking, isn't a superposition a linear sum of pure states? AG

Right.  And a linear sum of vectors is a vector.

Brent


    And every set of basis vectors is equivalent to, and
    indistinguishable from any other set of basis vectors. This
    shows that Schrodinger could have denied the usual
    interpretation of the WF as a superposition where the system it
    represented could be interpreted as being in all pure states in
    its sum simultaneously, without constructing his Cat experiment.
    He simply had to remind his colleagues that the set of basis
    vectors in a vector space is not unique. AG -- You received this
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