In order to figure out what is "not working",
I had to duplicate some data and copy your code.
I think the problem is pretty simple.
In your countif function, you're counting ALL the cells in "aRange"
not the row you're working on!
so, replace aRange with:
Range(Cells(j, 3), Cells(j, 42))
also, just to clean it up a bit.
If your macro finds, say, 17 values > 0, then it will put the
number "17" in column 11... SEVENTEEN TIMES!
(once for each value it finds)
I think after you put the NumberofMonths in column 11, you should add:
Exit For
hope this helps,
paul
________________________________
From: c <cad...@gmail.com>
To: MS EXCEL AND VBA MACROS <excel-macros@googlegroups.com>
Sent: Friday, October 2, 2009 1:01:03 AM
Subject: $$Excel-Macros$$ Help with CountIf in Macro
Hi Everyone,
Need some help with this macro. Basically, I am searching through
rows and looking for any values in the cells that are >0 in columns AR
- CE.
After I find these cells in that range, I need to count the number of
columns. This can be done with the COUNTIF function. I also do not
want to count blank cells.
I want to put the result of the countif in the K column.
Here is what I have so far and it's not working. Go figure. Please
help. I think I'm close.
Dim j, k As Long
Dim iRow As Long
Dim aRange As Range
Dim NumberOfMonths As Long
Dim WS1 As Worksheet
Set WS1 = Worksheets("Dept")
NumberOfMonths = 0
Sheets("Dept").Select
With WS1.Range("AR2:CE250")
Set aRange = WS1.Range("$AR$2:$CE$250")
For j = 2 To aRange.Rows.Count
For k = 44 To 90
If ((WS1.Cells(j, k) > 0)) Then
NumberOfMonths = Application.WorksheetFunction.CountIf
(aRange, ">0")
WS1.Cells(j,11).Value = NumberOfMonths
End If
Next k
Next j
End With
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