Hi rajan
Can you explain
below code
st = st & vbTab & Arr(Rw, Cl)
Next
st = st & vbCrLf
Next
St means ?
On Sun, Jul 24, 2011 at 1:08 PM, Rajan_Verma <rajanverma1...@gmail.com>wrote:
> See if it Helps
>
> Option Base 1
> Sub StoreInArrya()
> Dim Arr() As Variant
> Dim rng As Range
> Dim Rw As Integer
> Dim Cl As Integer
>
> Set rng = Range("A1:C5")
> ReDim Arr(rng.Cells.Rows.Count, rng.Cells.Columns.Count)
>
> For Rw = 1 To rng.Rows.Count
> For Cl = 1 To rng.Columns.Count
> Arr(Rw, Cl) = rng.Cells(Rw, Cl).Value
> Next
> Next
>
> For Rw = 1 To rng.Rows.Count
> For Cl = 1 To rng.Columns.Count
> st = st & vbTab & Arr(Rw, Cl)
> Next
> st = st & vbCrLf
> Next
> MsgBox st
> End Sub
>
> -----Original Message-----
> From: excel-macros@googlegroups.com [mailto:excel-macros@googlegroups.com]
> On Behalf Of netuser501
> Sent: Sunday, July 24, 2011 6:42 AM
> To: MS EXCEL AND VBA MACROS
> Subject: $$Excel-Macros$$ vba for loops -beginner
>
> Hi
>
> The question worksheets is filled with data on 5 rows and 3 columns.
> I'd like to have this data stored in an Array. For testing purpose, I
> want to test if the loop is "reading" the data with an integer "tmp"
> that should return the number of cells filled in with data.
>
> Set wkb = ThisWorkbook
> Set wks = wkb.Worksheets("questions")
>
>
> For i = 0 To wks.Cells(i + 1, 1 = ""
> For j = 0 To wks.Cells(i + 1, j + 1) = ""
> tmp = tmp + 1
> Next j
> Next i
>
> Why aren't Loop j and i looping?
>
>
>
> Another question :
>
> Is this possible to redim an array in a 2d for loop :
>
> dim SomeArray() as variant
> redim SomeArray(0,0) 'A
>
> for i = 0 to MAXL
> for j = 0 to MAXC
> SomeArray(i,j) = cells(i+1,j+1)
> redim preserve SomeArray(i,j+1)
> next j
> redim preserve SomeArray(i+1,j) 'j has still MAXC as value
> next i
>
> I understand it's not making sense since MAXL and MAXC could be
> declared in A.
>
> Back to the previous question it would make sense to redim a 2d array
> in a for loop until a cell is empty in the column and a cell is empty
> in the lines.
>
> Thanks for your precious help,
>
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